swift - Does setting `constraint.isActive = false` deallocate the constraint? -

say want remove constraint, traditionally do:

view.removeconstraint(constraint) 

however, there new isactive methods installing/uninstalling constraints.

if following:

constraint.isactive = false 

will remove memory correctly?

yes,

constraint.isactive = false 

is doing same thing as:

viewthatownsconstraint.removeconstraint(constraint) 

so if thing holding on constraint view, correctly remove memory.

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here's proof:

let view = uiview()  weak var weakview: uiview? = nil autoreleasepool {   weakview = uiview() } assert(weakview == nil)  // traditional way of removing constraints ensures constraint deallocated  weak var weakconstraint: nslayoutconstraint? = nil autoreleasepool {   weakconstraint = view.widthanchor.constraint(equaltoconstant: 10) } assert(weakconstraint == nil) // nothing holding on constraint  autoreleasepool {   weakconstraint = view.widthanchor.constraint(equaltoconstant: 10)   view.addconstraint(weakconstraint!) } assert(weakconstraint != nil)  autoreleasepool {   view.removeconstraint(weakconstraint!) } assert(weakconstraint == nil)  // new way of removing constraints:  assert(weakconstraint == nil)  autoreleasepool {   weakconstraint = view.widthanchor.constraint(equaltoconstant: 10)   weakconstraint!.isactive = true } assert(weakconstraint != nil)  autoreleasepool {   weakconstraint!.isactive = false } assert(weakconstraint == nil)