mysql - Using LIKE when searching for "%" -

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this question has answer here:

i want check whether column starts "%". if search character code below doesn't work when searching "%". 

select * `table` `column` 'anothercharacter%'

thanks.

you can try this

select * `table` column 'anothercharacter%[%]%'

or

where column '%\%%' escape '\'

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