c - Can anyone help me with this code? -

i think logic correct it's not printing anything. code eliminate vowel string , display it.

 #include<stdio.h>  #include<conio.h>   void main()   {     char *str="shivank";     int i,len;    char *q;     clrscr();      len=strlen(str);     for(i=0;i<=len;i++)      {            if((*str=='a')||(*str=='e')||(*str=='i')||(*str=='o')||(*str=='u'))             str++;              else if(*str=='\0')                    break;            else              {                   *q=*str;                str++;              q++;            }      }      *q='\0';      puts(q);        getch();     }  

if understand correctly, want transform "shivank" "shvnk", , store in seperate string print later.

you have allocate memory somewhere. working pointers won't work - @ best, change str point different beginning of string: "hivank", "ivank", "vank" etc.. possible using pointer arithmetics, that's it.

i recommend use char arrays instead of using string constants:

char str[] = "shivank"; char modified_str[10]; // enough memory store modified string 

the advantage of using arrays can modify them example:

modified_str[0] = str[0]; 

(this example copies first letter of str first letter of modified_str)

then read characters of str string 1 one, , copy non-vowels modified_str. don't forget end modified_str '\0'.