Convert 2016-08-27 string to date in hive -
i using code below convert date format output null.
select from_unixtime(unix_timestamp(b.temp,'yyyymmdd'), 'yyyymmdd') temp1 ([![enter image description here][1]][1] select a.*, regexp_replace(a.ao_date,'-','') temp clla_samp_base ) b ;
any appreciated!
2016-08-27
in iso date format date format acceptable hive "as is".
hive> select cast ('2016-08-27' date) dt; ok dt 2016-08-27
p.s.
if have column containning values in format, can define column type date in first place.
Comments
Post a Comment